Century Table 700–1799 4 (Still Julian Calendar in Great Britain and its colonies until 1752) 1800–1899 2 1900–1999 0 2000–2099 6 2100–2199 4 2200–2299 2 2300–2399 0 2400–2499 6 2500–2599 4 2600–2699 2 Months Table January 0 (in leap year 6) February 3 (in leap year 2) March 3 April 6 May 1 June 4 July 6 August 2 September 5 October 0 November 3 December 5 Days Table Sunday 0 Monday 1 Tuesday 2 Wednesday 3 Thursday 4 Friday 5 Saturday 6 Example ------- Find day of week for 1 August 2010 1. Look up the 2010 in the centuries table: 6 2. Note the last two digits of the year: 10 3. Divide the 10 by 4: 10/4 = 2.5 and drop the fractional part: 2 4. Look up August in the months table: 2 5. Add all numbers from steps 1–4 to the day of the month (in this case, 1): 6+10+2+2+1=21. 6. Divide the sum from step 5 by 7 and find the remainder: 21/7= 3 remainder 0 7. Find the remainder in the days table: 0 = SUNDAY Answer is SUNDAY Let's try leap year January 1, 2000 1. Look up the 2000s in the centuries table: 6 2. Note the last two digits of the year: 00 3. Divide the 00 by 4: 0/4 = 0 and drop the fractional part: 0 4. Look up January in the months table: 6 (leap) 5. Add all numbers from steps 1–4 to the day of the month (in this case, 1): 6+00+0+6+1=13. 6. Divide the sum from step 5 by 7 and find the remainder: 13/7=1 remainder 6 7. Find the remainder in the days table: 6=Saturday. Now let's use April 24, 1982. 1. Look up the 1900s in the centuries table: 0 2. Note the last two digits of the year: 82 3. Divide the 82 by 4: 82/4 = 20.5 and drop the fractional part: 20 4. Look up April in the months table: 6 5. Add all numbers from steps 1–4 to the day of the month (in this case, 24): 0+82+20+6+24=132. 6. Divide the sum from step 5 by 7 and find the remainder: 132/7=18 remainder 6 7. Find the remainder in the days table: 6=Saturday.